Web1 dec. 2024 · MathPhys Answer: 12 Step-by-step explanation: h (x) = f (g (x)) Using chain rule: h' (x) = f' (g (x)) g' (x) h' (1) = f' (g (1)) g' (1) h' (1) = f' (2) g' (1) h' (1) = -4 × -3 h' (1) = 12 Advertisement 30 POINTS. I NEED HELP. [20 POINTS] The ordered pair (a,b) satisfies the inequality y>x+3. Web3 Answers Sorted by: 2 You should be asking "find h ′ ( x) if h ( x) = f ( g ( x)) ". Use the chain rule: [ f ( g ( x))] ′ = f ′ ( g ( x)) ⋅ g ′ ( x). We aren't told what f is, but we do know …
Composition of Functions - Definition, Properties and Examples
WebIf h (x) = (fog) (x), then h' (3) = Q. Let f and g be differentiable functions such that f (3) = 5,g(3) = 7,f ’(3) = 13,g’(3) = 6,f ′(7) = 2 and g′(7) = 0. If h(x) = (f og)(x), then h′(3) = 1865 50 KEAM KEAM 2024 Report Error A 14 B 12 C 16 D 0 E 10 Solution: h(x) = f (g(x)) h′(x) = f ′(g(x))⋅ g′(x) h′(3) = f ′(g(3))⋅ g′(3) [∵ g(3) = 7g′(3) = 6] Web4 mrt. 2024 · Explanation: Given: ⎧⎪ ⎨⎪⎩f (x) = x2 + 1 g(x) = 2x h(x) = x − 1. One way of thinking about these function compositions is to go back and forth between the symbols … pistol to head
If h(x) = x3 + x and g(x) = 2x +3, then g(h(2)) - Brainly.com
WebTherefore, F(x) + G(x) is an antiderivative of f(x) + g(x) and we have ∫(f(x) + g(x))dx = F(x) + G(x) + C. Similarly, ∫(f(x) − g(x))dx = F(x) − G(x) + C. In addition, consider the task of finding an antiderivative of kf(x), where k is any real number. Since d dx(kf(x)) = k d dxF(x) = kf ′ (x) for any real number k, we conclude that Web2 jan. 2014 · Find h' (1)? Let f and g be differentiable functions such that f (1)=2, g (1)=2, f' (1)=3, g' (1)=-3, f' (2)=-4, g' (2)=5. If h (x)=f (g (x)), find h' (1). Answer: 12 Follow • 2 … WebWe then need to find a function that is equal to h(x) = f(x)/g(x) for all x ≠ a over some interval containing a. To do this, we may need to try one or more of the following steps: If f(x) and g(x) are polynomials, we should factor each function and cancel out … pistol-training.com